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hw help
http://www.arwen-undomiel.com/forum/viewtopic.php?f=45&t=5164		 Page 1 of 1
Author:  pip&leggyluvr [ January 10th, 2006, 7:06 pm ]
Post subject:  hw help
ok, this is kinda dumb, but i really do need help. can ne of u guys help me w/ my math hw? lol
I hate this stuff!!! :'( it makes no sense. ne help?
Author:  Jax Nova [ January 10th, 2006, 7:08 pm ]
Post subject: 
I would help.... but I am afraid that math is what makes my brain go dead..... the day I understand it I will go party... or something biger... like... I'll figure something out.

But I do hope you find somone to help you and I wish you luck!
Author:  pip&leggyluvr [ January 10th, 2006, 7:12 pm ]
Post subject: 
cum on, there's gotta be sum1 here who's good @ Math!!! plz!!!! :(
Author:  Jax Nova [ January 10th, 2006, 7:27 pm ]
Post subject: 
What is it? I supose I could give it a try.
Author:  pip&leggyluvr [ January 10th, 2006, 7:30 pm ]
Post subject: 
ya!!! lol thank u!!! it's, ok, u have like a rectangle & then there's a smaller rectangle inside it &.... :confused: OK, here's the problem:
a rectangle is twice as long as a it is wide. If both dimensions are increased by 4 m, its area is increased by 88m2. (the 2 is really squared, but idk how 2 make it smaller.) Make a sketch & find the dimension of the original rectangle. :confused2: help!!!

OK, i have 2 go eat dinner, so if ne1 can plz help me, (as u can c i'm totally desperate right now, cuz i suck @ math!! lol) post it, & hopefully i'll get it. (o, & by the way, i'm really slow, so if u can help me, plz right it very simply. no big words. not good w/ those. lol)
THANK YOU!!!!
:bye2:
Author:  Jax Nova [ January 10th, 2006, 7:37 pm ]
Post subject: 
@_@ AH!!!!! That's what I'm worst at!!!! sorry.

I HATE those things!!

I can't get it... sorry
Author:  Arwen the webmaster [ January 10th, 2006, 8:13 pm ]
Post subject: 
I hate math too, but years of stupid prep for tests made me get it, so I went ahead and solved the problem for you. I'll try to explain it...

Image

N is the height; 2N is the width, since the rectangle is twice as wide as the height. The area is 2N<sup>2</sup> (N times 2N). This is area #1.

Image

Here's the next rectangle, with 4 added to each side. Multiple the sides by each other (N + 4 times 2N + 4), and you get 2N<sup>2</sup> + 12N + 16.

Now the problem states that the rectangle with 4 added to each side is 88m<sup>2</sup> more than the original rectangle. So if we subtract the area of the first rectangle from the area of the second rectangle, we'll get 88m<sup>2</sup>. 2N<sup>2</sup> + 12N + 16 minus 2N<sup>2</sup> is 12N + 16. And since our answer is supposed to be 88m<sup>2</sup>, 12N + 16 = 88. Subtract 16 from both sides; you get 12N = 72. Divide by 12 on both sides, and N = 6. Now plug into the rectangles. On the first rectangle, you'll have a height of 6 (N) and a width of 12 (2N). On the second rectangle you'll have a height of 10 (N + 4) and a width of 16 (2N + 4).

Now to double check, multiply the height and width of the first rectangle to get 72, and multiply the height and width of the second rectangle to get 160. Subtract 72 from 160, and you get - surprise surprise - 88.

Hope that helped!
Author:  pip&leggyluvr [ January 10th, 2006, 8:56 pm ]
Post subject: 
O!!! OK!!! i get it now!!! YHA!!!! :wave: :lol: :jump: :goofy:
lol thank u so0o0o much!!! now i have 2 call all my friends back & tell them how 2 do it. lol thank u!!!! :-D
:bye2:
:angel: <you
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